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Corporal_Armstro

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  1. Yes, example one correct. Though a reroll, generally defined as a second chance in the event of failure is resolved differently, The effect this has on the outcome is as follows. First, you have the odds to succeed on the first roll. If you pass the first roll, the second roll doesn't matter. If you fail, though, you get to try again. So, the odds can be described as, the chance that you succeed, plus the chance that, if you fail, you succeed on the second attempt. Mathematically, this looks like (chance to succeed) + (1-chance to succeed)*(chance to succeed). If you want to use algebra, you can also write this as 2*(chance to succeed) - (chance to succeed)squared.
  2. Did you ever do statistics and probability at school? The odds will always stay the same, but probability suggests that the chance of successive failures reduces every time. For Eg. I have 2 dice and my aim is to roll a 4 ,5 ,6. My odds are 50% per dice, but by probability which is 2 x .5 = 1 Say if my goal is unchanged but instead of rolling two dice at once, I get a reroll. In this case it would then be 1 x .5 = .5 1.5 x .5 = .75 So in the realms of probability I have a greater chance of rolling a 4 ,5 ,6 with 2 dice than with rolling the one twice. So in which the odds for an RE is always .2 or .1, each successive roll would then be 1.2 x the proceeding. The odds are ALWAYS the same, my probability just increases. If we put the above example into the question of RE probability it is: 1 x .2 = .2 1.2 x .2 = .24 1.24 x .2 = .248 And so on. I'm a glass half full kind of guy. I like to think positive.
  3. Never tell me the odds! .2 .24 .288 .3456 .41472 .497664 .5971968 .71663616 .859963392 1.03195607 or you could just look at it simply and go 5 x .2 = 1 If the odds are in your favor you should at least see your schematics by your tenth attempt. Not that this will help you in the game in any way as each roll is independent of the last. Then again it really depends on how you look at it.
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